The 10th term from the end of the A.P. -5, -10, -15,…, -1000
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Step-by-step explanation:
a = -5
l = -1000 = a_n
d = -10-(-5)
= -10+5
= -5
From the relation, a_m=a+(m-1)d
-1000 = -5+(m-1)-5
-1000 + 5 = (m-1) -5
-995/-5 = (m-1)
199 = m-1
m = 200
so coming to our question 10th term from end is
a+(m-n)d
= -5+(200-10)-5
= -5+(190)-5
= -5-950
= -955
Therefore 10th term from end is -955.
Thank you
Hope it helps. mate....
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