The 10th term from the end of the A.P. -5, -10, -15,…, -1000 is (a) -955 (b) -945 (c) -950 (d) -965
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Answer:
The given question is solved in the uploaded photo.
Extra information-
mth term from the end of an ap containing n terms is (n-m+1)th term from beginning.
The simplest way to do this is to assume last term as the first term and find nth term from the end of AP.
That is , l=-1000
d=5 and n=10
Now,
l10=l+(n-1)d= -1000+(10-1)5=-955(ans)
Hence the given question is solved in two ways
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