Question

the 10th term from the end of the A.P. 5,12,19,.........173.​

Answer 1

Answer:

Given

AP- 4,9,14........254

Last term of AP is 254

Since it is been asked to find the 10th term from end; a=254

d=−5,n=10

a

n

=a+(n−1)d

a

n

=254+(10−1)(−5)

a

n

=254−45

a

n

=209

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

5,12,19,.........173

here,

first term, a = 5,

common difference, d = 12-5=19-12=...=7

last term = 173

if we write the A.P. inversely, then we'll get, a=173, d=-7

therefore,

the 10th term from the end

= 173+9(-7)

=173-63

=110