Question

the 10th term from the end of the AP 10 ,14,18,22...496 is.
a)400
b)410
c)460
d)500​

Answer 1

Given  :  AP   10 ,14,18,22...496  

To Find :   10th term from the end of the AP

Solution:

from beginning

a = 10

d = 14 - 10  = 4

from end

a = 496

d = - 4

10th term of end

=  496 + (10 - 1) (-4)

= 496 - 36

= 460

But actually data has mistake

as 496 can not be term of the AP

496 = 10 + (n - 1) 4

=> 486/4 = n - 1

=> 121.5 = n - 1

=> n = 122.5

Hence n is not an integer

So data has mistake

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