The 10th term of a geometric progression is 8 times the 13th term. The first term
is 3. Then find the sum up to infinite terms.
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ar^(9) = 8×ar^(12)
3×r^(9) = 8×3× r^(12)
r^(9) =8×r^(12)
r^(3)=1/8
r = 1/2
sum up to infinite terms = a/(1-r)
=3/{1-(1/2)}
=3/(1/2)
=6
3×r^(9) = 8×3× r^(12)
r^(9) =8×r^(12)
r^(3)=1/8
r = 1/2
sum up to infinite terms = a/(1-r)
=3/{1-(1/2)}
=3/(1/2)
=6
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