Question

The 10th term of an
A.p 5,9, 13,....is​

Answer 1

$a = 10 \: \: \: \: \: \: \: \: d = 4 \\ t10 = a + (10 - 1)d \\ t10 = 10 + (9)4 \\ = 10 + 36 \\ = 46$