Question

The 10th term of
an AP 5,9.13

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Answer 1

Step-by-step explanation:

Given :

a = 5 , d = 4 ,n = 10

we know that,

$\color{gold}an=a+(n-1) d$

Substituting the given values,

=> a10 = 5 + 9(4)

= 5 + 36

= 41

Therefore the 10th term is 41

Answer 2

Answer:

A.P = 5,9,13,........

a = 5

d= 4

10th term = a + (n-1)d

= 5 + (10-1)4

= 5+9×4

= 5+36

= 41