The 10th term of an AP is 25 and 18th term is 41. find the
14th term of this AP .
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An = a+(n-1) d
A10 = a +9d. =25. (equ. 1)
A18 =a+17d =41. (equ. 2)
(equ.2) - (equ.1)
=. a+17d - (a+9d). = 41-25
=. a-a+17d-9d = 16
= 8d =16
=. d =2
putting d=2 in equ. 1
a+ 18 = 25
a = 7
A14 = a+13d
= 7+ 26 = 33
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