Question

The 10th term of an AP is 32 and its 12th term is 52. Find the AP

Answer 1

$a + 11d = 52$

$a + 9d = 32$

By equating them both we get,

$2d = 20$

$d = 10$

And by eq 1 we can find the value of

$a$

So,

$a + 11(10) = 52$

$a = 52 - 110$

$a = - 58$

By subtrating 10 we will get the next term

As

-58,-58-10=-68,-68-10=-78.....

AP : -58,-68,-78

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