The 10th term of an ap is 47. And it's 15th term is 72. Find the ap
Answers
Answered by
8
Heya!!!
Answer to your question:
We know,
T=a+(n-1)
a+(10-1)d=47
a+9d=47
a=47-9d---(i)
a+(15-1)d=72
a+14d=72----(ii)
using (i) in (ii),
47-9d+14d=72
5d=72-47
5d=25
d=5
Put value of d in (i)
a=47-9 (5)
=47-45=2
A.P.=2,2+5,2+2 (5),......
=2,7,12....
Hope it helps ^_^
Answer to your question:
We know,
T=a+(n-1)
a+(10-1)d=47
a+9d=47
a=47-9d---(i)
a+(15-1)d=72
a+14d=72----(ii)
using (i) in (ii),
47-9d+14d=72
5d=72-47
5d=25
d=5
Put value of d in (i)
a=47-9 (5)
=47-45=2
A.P.=2,2+5,2+2 (5),......
=2,7,12....
Hope it helps ^_^
Answered by
7
a+9d=47
a+14d=72
-. -. -
-5d= -25
minus to minus cancel
d=5
Put d= 5 in eqn. 1
a+9(5) = 47
a+45=47
a=2
Ap = 2,7,12....
Here is the answer.......
a+14d=72
-. -. -
-5d= -25
minus to minus cancel
d=5
Put d= 5 in eqn. 1
a+9(5) = 47
a+45=47
a=2
Ap = 2,7,12....
Here is the answer.......
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