The 10th term of an AP is 52 and 16th term is 82 find
(iii) sum of first 20 terms of an AP
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Step-by-step explanation:
Let a be the first term and d be the common difference of the given A.P.
Let the A.P. be a1,a2,a3,....,an,...
It is given that
a10=52 and, a16=82
⟹a+(10−1)d=52 and, a+(16−1)D=82
⟹a+9d=52 ...(i)
and a+15d=82 ...(ii)
Subtracting equation (ii) form equation (i), we get
−6d=−30⟹d=7
Putting d=5 in equation (i), we get
a+45=52⟹a=7
∴a32=a+(32−1)d=7+31×5162
and, an=a+(n−1)d=7(n−1)×=5n+2
Hence, a32=162 and an=5n+2
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