Question

the 10th term of an AP IS 52 and 16th term is 82. find the 32nd term.. ​

Answer 1

Step-by-step explanation:

10th term=a+9d=52

16th term=a+15d=82

a+9d=52

a+15d=82

=6d=30

d=30÷6

d=5

substitute d=5 in equ 1

a+9(5)=52

a+45=52

a=52-45

a=7

32nd term=

a+31d

7+31(5)

7+155

=162

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Answer 2

Step-by-step explanation:

a+31d=a32

7+31×5=a32

7+155=a32

162=a32

a&d come forward

when you solve a10&a16