the 10th term of an AP IS 52 and 16th term is 82. find the 32nd term..
Answers
Answered by
23
Step-by-step explanation:
10th term=a+9d=52
16th term=a+15d=82
a+9d=52
a+15d=82
=6d=30
d=30÷6
d=5
substitute d=5 in equ 1
a+9(5)=52
a+45=52
a=52-45
a=7
32nd term=
a+31d
7+31(5)
7+155
=162
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Answered by
3
Step-by-step explanation:
a+31d=a32
7+31×5=a32
7+155=a32
162=a32
a&d come forward
when you solve a10&a16
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