Question

The 10th term of an arithmetic progression 1,5,9,13___ is

Answer 1

Answer:

a = 1 , d= 4

an = a+(n-1)d

= 1 +(10-1) × 4

= 1+ 36

= 37 .

so the 10th term of an AP is 37

Answer 2

Answer:

37

Explanation:

IN the given AP

first term = a= 1

d = t2-t1 = 5-1=4   d=4

The nth term of an AP is

tn = a + (n-1)d

therefore, t10 = 1 + ( 10 - 1 )x 4

                      = 1+ 9 x4

                      = 1+36

                t10= 37