The 10th term of an arithmetic sequence is 42 and the 16th term is 60 . Find the first term .
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a10=42=a1+(10-1)d=a1+9d, 1st equation
a16=60=a1+(16-1)d=a1+15d, 2nd equation
Subtract 1st equation from 2nd, you will get
18=6d, d=3
Put this value of d in any of the above equations, you will get a1=15=1st term
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