Math, asked by muralimuralicn35, 1 month ago

The 10th term of an arithmetic sequence with common difference 3 is 34 . is 127 a term of this sequence.​

Answers

Answered by harikrishnadeka3
0

Answer:

given,

d=3

a10=34

a+(10-1)3=34

a+9×3=34

a+27=34

a=34-27

a=7

Now,

an=127

a+(n-1)d=127

7+(n-1)3=127

7+3n-3=127

3n+4=127

3n=127-4

3n=123

n=123/3

n=41

therefore 127 is the 41th term of the sequence.

Similar questions