The 10th term of an arithmetic sequence with common difference 3 is 34 . is 127 a term of this sequence.
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Answer:
given,
d=3
a10=34
a+(10-1)3=34
a+9×3=34
a+27=34
a=34-27
a=7
Now,
an=127
a+(n-1)d=127
7+(n-1)3=127
7+3n-3=127
3n+4=127
3n=127-4
3n=123
n=123/3
n=41
therefore 127 is the 41th term of the sequence.
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