Question

the 10th term of ap:2,6,9....

Answer 1

Answer:

Given sequence not an A.P

Step-by-step explanation:

Given sequence : 2,6,9,....

First term (a) = 2,

$a_{2}-a_{1}= 6-2 = 4$

$a_{3}-a_{2}= 9-6 = 3$

$a_{2}-a_{1}≠a_{3}-a_{2}$

Therefore,

Given sequence not an A.P

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