Question

the 10th term of AP is 1 and 20th term is -29 find 3rd term

Answer 1

A+9d=1
A+19d=-29
-10d=30
D=-3
A=28
so 3term is =a+2d
28-6
22 ok plz Mark it as a brainliast

Answer 2

Concept:

The difference between any two consecutive integers in an arithmetic progression (AP) sequence of numbers is always the same amount. It also goes by the name Arithmetic Sequence. For instance, the natural number sequence 1, 2, 3, 4, 5, 6,... is an example of an arithmetic progression. It has a common difference of 1 between two succeeding terms (let's say 1 and 2). (2 -1). We can see that the common difference between two subsequent words will be equal to 2 in both the case of odd and even numbers.

Nth term of an AP be,

Tₙ=a+(n-1)d

Sum of N terms in an AP

Sₙ=n/2(2a+(n-1)d

Given:

The 10th term of AP is 1 and 20th term is -29

Find:

Find third term

Solution:

A+9d=1------------i

A+19d=-29--------ii

On subtracting eq i and  ii,we get

⇒-10d=30

⇒D=-3

Using this value in eq i

A=28

so third term is =a+2d

                           =28-6

                           =22

Therefore, the value of third term is 22

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