The 10th term of aritgemetice progression -3 -1 1 3
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10th term of given A. P. -3 , -1 , 1 , 3 Here a = -3 , d = -1 - (-3) = -1 +3 = 2 Now nth term of an A. P. = a + ( n - 1 ) d . therefore, 10th term = - 3 + (10-1) ×2 = -3 + 18 = 15
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