The 10th term of sequnce √3,√12,√27 is
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- 10th term of given AP is 10√3.
Step by step explanation:
Given:
- AP = √3, √12, √27....
To Find:
- 10th term of given AP.
Now, we can write
=> √12 = 2√3
=> √27 = 3√3
Now, AP becomes, √3, 2√3, 3√3....
Now, we will calculate common difference,
=> d = a₂ - a₁
=> d = 2√3 - √3
=> d = √3
Now, we will calculate 10th term of an AP,
=> aₙ = a + (n - 1)d
=> a₁₀ = √3 + (10 - 1)√3
=> a₁₀ = √3 + 9√3
=> a₁₀ = 10√3
Hence, 10th term of given AP is 10√3.
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