Question

The 10th term of the Ap -3,-1, 1,3 ...is​

Answer 1

Answer:

The 10th term of the Ap -3,-1, 1,3 ...is 15

Step-by-step explanation:

The 10th term of the Ap -3,-1, 1,3

a = –3

d = –1 –(–3) = –1 +3 = 2

$\implies \: \: a_{10} = - 3 + (10 - 1)2 \\ \\ \implies \: \: a_{10} = - 3 + 18 \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \implies \: \: a_{10} = 15 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Answer 2

$\large\sf\underline\red{Answer \: :-}$

Given :-

• First term = a = -3
• AP = -3,-1, 1,3

To find :-

• 10th term

First,

We find the difference in each term.

$\sf\implies{t_2- t_1 } \: \: \: \: \: \: \: \: \: \: \: \: \\ \\\sf\implies{ ( - 1) - ( - 3) } \\ \\\sf\implies{ 2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Using formula

${\pink{\bigstar}} \: \:{\underline{\boxed{\sf{\red{S_n = a + ( n - 1 ) d }}}}}$

By using,

$\sf\dashrightarrow{S_{10} = -3 + (10-1)-2} \\ \\ \sf\dashrightarrow{S_{10} = -3 + (9)2} \: \: \: \: \: \: \: \: \: \\ \\ \sf\dashrightarrow{S_{10} = -3 +( 18)} \: \: \: \: \: \: \: \: \: \: \: \\ \\ \sf\dashrightarrow{S_{10} = 21} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

The 10th term is 21.

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