The 10th term of the AP is 41 and the 18th term is 73 find the 26th term
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a+9d=41, equation 1
a+17d =73 equation 2
subtraction equation 2 from 1 we get i.e
a+17d=73
a+9d=41
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so it comes 8d=32 and d =4
putting the value of d in equation 1 we get
a+9*4=41 So value of a =5
to find the 26th term the formula is
a+(n-1)*d here a=5,d=4 and n= 26
so 5+(26-1)*4=5+100 is 105
so the answer or the 26th term is 105.
HOPE ITS MIGHT BE HELPFUL
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