the 10th term of the seq^n √3,√12,√27,......
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Step-by-step explanation:
Given the 10th term of the seq^n √3,√12,√27,...
- We need to find the 10th term of the given sequence.
- So we have first term a = √3, d = √12 - √3 = 2√3 - √3 = √3 and n = 10
- Now we have Tn = a + (n – 1)d to find the 10 th term.
- So T10 = √3 + (10 - 1)√3
- = √3 + 9 √3
- = √3 (1 + 9)
- = 10 √3
- So the 10th term of the sequence is 10 √3
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The 10th term of the sequence √3,√12,√27,... is 10√3
Step-by-step explanation:
The given sequence is:
√3, √12, √27,... = √3, √(3 × 4), √(3 × 9),....
⇒ √3, √12, √27,... = √3, 2√(3), 3√(3),....
The nth term is given by the formula:
Nn = a + (1 - n)d
Where,
a = First term = √3
d = Common difference = 2√3 - √3 = √3
Now, the 10th term is:
N10 = √3 + (1 - 10)√3
N10 = √3 + 9√3
∴ N10 = 10√3
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