The 10th term of the series 13, 8, 3, -2… is
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The 10th term of the series 13, 8, 3, -2… is 33.
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Answer:
a=13
d=a2-a1 = 8-13
d=(-5)
n=10
an=a+(n-1)d
a10=13+(10-1)(-5)
=13+9(-5)
=13-45
=-32
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