The 10th term of the series 13, 8, 3, -2… is
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Answered by
2
EXPLANATION
- GIVEN
series are = 13,8,3,-2,........
TO FIND 10TH TERM OF AP
Let the first term of series = 13
common difference= b - a
=> 8 - 13 = -5
FORMULA FOR NTH TERM OF SERIES
An = a + ( n - 1 ) d
T10 = a + 9d
13 + 9 (-5)
13 - 45
-32 = ANSWER
Hence,
10th term of Ap = -32
Answered by
0
Answer: 58
Step-by-step explanation
d= 8-13=5
a= 13
n=10
T10= from nth term Tn =a+(n-1)d
T10= 13+(10-1)5
=13+(9)5
=13+45=58
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