Question

The 10th term ➡ the sequence √3,√12,√27,.........is √3n2Find value ➡ n
2 ​

Answer 1

Solution:-

To Find:-

Value of "n" = ?

Find:-

a = √3

d = (√12 - √3).

A.T.Q.

A10 = √3n²

=> a + ( 10-1) d = √3n²

=> √3 + 9( √12 -√3) = √3n²

=> √3 + 9√12 - 9√3 = √3n²

=>√3 + 9×2√3 - 9√3 = √3n²

Multiplying by √3 in both the sides,

=>√3 ( √3 + 18√3 - 9√3) = √3 × √3 n²

=> 3 + 18×3 - 9×3 = 3 n²

=> (3 + 54 - 27)/3 = n²

=> 30/3 = n²

=> 10 = n²

=> n = √10

Hence,

The Value of n is √10.

Answer 2

Answer:

hey here asking n/2 know?

Step-by-step explanation:

then answer is 5