The 10th tern of an arithmetic progression is 47 and its first term is 2 then what will be its common difference
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Answered by
11
Hi,
10th term of ap is 47 i.e
a+9d=47
now,
a=2
substitute the value of a in equation
we get:2+9d=47
i.e9d=47-2
i.e 9d=45
i.ed=45/9
we get d=5
10th term of ap is 47 i.e
a+9d=47
now,
a=2
substitute the value of a in equation
we get:2+9d=47
i.e9d=47-2
i.e 9d=45
i.ed=45/9
we get d=5
Answered by
8
a+9d=47
a=2
d=?
2+9d=47
10d=47-2
10d=45
d=45/9
d=5
a=2
d=?
2+9d=47
10d=47-2
10d=45
d=45/9
d=5
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