Question

the 10th trrm of an AP 5,9,13, is​

Answer 1

EXPLANATION

$&#10155$ Given A.P 5,9,13

FORMULA

$&#10155$ nth term of an A.P

$a_{n} = a + (n - 1)d$

where, a = first term of A P

n = total term of an A P

d = difference between two term

SOLUTION

$&#10155$ A.P = 5,9,13

a = 5 , d = 9–5 = 4

now 10th term of A.P

$\implies \: \: a_{10} = 5 + (10 - 1)4 \\ \\ \implies \: \: a_{10} = 5 + 36 \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \implies \: \: a_{10} = 41 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$