the 11 term of an ap exceeds its fourth term by 14 find the common difference
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D= 2
As
ATQ
a+ 10d = a+ 3d+ 14
10d- 3d = 14
7d = 14
d = 2
hope it will help you
As
ATQ
a+ 10d = a+ 3d+ 14
10d- 3d = 14
7d = 14
d = 2
hope it will help you
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