the 11 term of an ap is 5 more than twice its a term if the 11 term of an ap is 43 then find the nth term
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Hey mate please recheck your question once....because how can both the condition of ap is given for 11th term only.....
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a11=2a1+5
a+10d = 2 (a+0d)+5
a+10d = 2a+5
a-10d = -5 ...... (i)
Now
a11=43
a+10d=43....... (ii)
Substract (i) from (ii)
20d=48
d=48/20=24/10=12/5
substitute d in (i)
a-10 (12/5) =-5
a-24=-5
a= 19
Now
nth term =a+(n-1)d
= 19+(n-1)12/5
= 19+12/5n-12/5
a+10d = 2 (a+0d)+5
a+10d = 2a+5
a-10d = -5 ...... (i)
Now
a11=43
a+10d=43....... (ii)
Substract (i) from (ii)
20d=48
d=48/20=24/10=12/5
substitute d in (i)
a-10 (12/5) =-5
a-24=-5
a= 19
Now
nth term =a+(n-1)d
= 19+(n-1)12/5
= 19+12/5n-12/5
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