The 11 term of Ap is (5a_x),6a,(7a+x)
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Answer:
15a + 9x
Step-by-step explanation:
AP is 5a-x, 6a, 7a+x ....
Tₙ = a + (n-1)d where a is the first term
First term = 5a - x
d = 6a - (5a - x) = 6a - 5a + x = a +x
T₁₁ = 5a - x + (11 - 1)(a+x) = 5a-x + 10a +10x = 15a + 9x.
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