Question

The 11 term of Ap is (5a_x),6a,(7a+x)

Answer 1

Answer:

15a + 9x

Step-by-step explanation:

AP is 5a-x, 6a, 7a+x ....

Tₙ = a + (n-1)d where a is the first term

First term = 5a - x

d = 6a - (5a - x) = 6a - 5a + x = a +x

T₁₁ = 5a - x + (11 - 1)(a+x) = 5a-x + 10a +10x = 15a + 9x.