Question

The 11th and 13th term of AP are 35 and 41 respectively then it's common differences​

Answer 1

Answer:

3

Step-by-step explanation:

Let the first term be 'a' and common difference be 'd'.

Using, aₙ = a + (n - 1)d,   where letters have their usual meaning.

⇒ 11th term = 35

⇒ a + 10d = 35      ...(1)

⇒ 13th term = 41

⇒ a + 12d = 41       ..(2)

Subtract (1) from (2):

 a + 12d = 41

 a  + 10d = 35

 -     -         -    

     2d    =  6  

2d = 6

d = 6/2 = 3

 

Answer 2

Answer:

11th term is 35 so a+10+d=35=>eq 1

13th term is 41 so a+12d =41=>eq 2

solve both eqs by elemination method we get common difference is 3