The 11th and 13th terms of an A.P. are 35 and 41 respectively its common difference is ..... (a) 38 (b) 32 (c) 6 (d) 3
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EXPLANATION.
=> 11th term of an Ap = 35
=> 13th term of an Ap = 41
To find the common difference.
Formula of Nth term of an Ap.
=> An = a + ( n - 1 ) d
=> a + 10d = 35 ........(1)
=> a + 12d = 41 .........(2)
Form equation (1) and (2) we get,
=> - 2d = -6
=> d = 3
put the value of d = 3 in equation (1) we get,
=> a + 10(3) = 35
=> a + 30 = 35
=> a = 5
Therefore,
First term = a = 5.
common difference = d = 3.
option [ D ] is correct answer.
Anonymous:
Nice :)
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