The 11th term and 21st term of an A.P.are 16 and 29 respectively then find 31 term of an A.P
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Step-by-step explanation:
- a11-16
- a+10d=16--equation1
- a21-29
- a+20d=29---equation
- subtracting 1 and 2
- a+10d=16
- -a-+21d=-21
- =-11d=-15
- d=15/11
- putd=15/11 in 1
- a+110/15=16
- 15a+110=240
- 15a=240-110
- a=130/15=26/3
- a31=26/3+30(15/11)
- =26/3+450/11
- 286+135/33
- =421/33
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