The 11th term and 21st term of an A.P. are 16 and 29 respectively, then find the 41 st term of that A.P.
(Use the 1st formula for the solution)
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Answer:
may be my answer helps you
Step-by-step explanation:
a11
=16
a
21
=29
a
11
=a+10d=16
a
21
=a+20d=29
applytheelliminationmethod
a+10d=16
a+20d=29
changethesignyouwillgatethevalueofd=
10
13
putthevalueofdinequation(1)
a+10×
10
13
=16
a+13=16
a=16−13
a=3
a
41
=a+40d
a
41
=3+40×
10
13
=3+4×13
=3+52
a
41
=55
Hence
the41
th
termofApis55
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