Question

the 11th term and the 21 th term of an A.P are16 are29 respectively then find. 1) 1st term and d
2) 34th term 3) n such that tn =55​

Answer 1

Step-by-step explanation:

1)3 and d=1.3

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Answer 2

Answer:

here a+10d=16

substitute d value

a+10x13/10=16

a=16-13

a=3