Question

The 11th term and the 21st term of an A.P. are 16 and 29 respectively, then find the
41th term of that A.P.

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Answer 1

Answer:

answer is attached above

Answer 2

Answer:

55

Step-by-step explanation:

we know,

11th term = a + 10d = 16

21st term = a + 20d = 29

- - -

------------------------------

-10d = -13

d = 13/10

so, a + 10(13/10) = 16

a = 16-13

a = 3

and 41th term = a+40d

= 3+40(13/10)

= 3+52

= 55 ... ans.