The 11th term and the 21st term of an A.P. are 16 and 30 respectively, then find the 16th term of that A.P.
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Answer:
Given ,
a + 10d = 16 -----(1)
a + 20d = 30 ------(2)
Equation (2) -- (1)
a+20d --(a+10d) = 30 -- 16
=> a+ 20d -- a -- 10d = 14
=> 10d = 14
=> d = 1.4
To find a :-
a + 10d= 16
=> a + 10 × 1.4 = 16
=> a + 14= 16
=> a = 2
Now ,
To find the 16th term of that A.P. :
a+ (16 --1)d
=a+ 15d
= 2 + 15×1.4
= 2 + 21
=23
The 16th term of that A.P. is 23
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