The 11th term and the 21st term of an A.P. are 16 and 30 respectively, then find the 16th term of that A.P.
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LET THE FIRST TERM = a AND THE COMMON DIFFERENCE = d
11TH TERM = 16
a+ 10 d = 16 equation 1
21st term = 30
a+ 29 d =30 equation 2
on solving equation 1 and 2
19 d =14
d = 14 /19
a= 290/190
therefore, 16 th term
= a + 15 d
= 290 /190 + 15 * 14 /19
= 29 /19 + 210/19
=239/19
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