The 11th term and the 21st term of an A.P are 16 and
39 respectively. then find the 45th term of that AP
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- The 11th term and the 21st term of an A.P are 16 and
- 39 respectively. then find the 45th term of that AP
Given :
11st term = 16 (1)
21st term = 39 (2)
From I and ii equation
a+10d= 16 (3)
a+20d=39 (4)
From 3 and 4 equation
10d= 23
D = 2.3
Putting value of D in equation 3
a+10(23/10)=16
a+23=16
a= -7
So, 45th term is
= a+(n-1)d
= -7+(45-1)2.3
= 94.2
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