the 11th term and the 21st term of an ap are 16 and 29 respectively then find the 41st term of that AP
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answer is 55 for this question
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It is given that,
a11 = 16 and a21 = 29
We know that,
an=a+(n-1)d
a11=a+(11-1)d
⇒16=a+10d
⇒a=16-10d ...1
a21=a+(21-1)d
⇒29=a+20d
⇒29=16-10d+20d from 1
⇒29-16=10d
⇒d=
13
10
...2
Putting the value of d in 1, we get
a=16-10x1.3=3
∴ a41=a+(41-1)d
=3+40x1.3
=55
Hence, the 41th term of the A.P. is 55
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