Question

The 11th term and the 21th term of an a.p. are 16 and 29 respectively,then find 41th term if that A.p

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

55

Step-by-step explanation:

In the given A.P. 11th term =16 & 21st term=29

we know that , tn = a+(n-1)d

16 =a+10d ....(I)

similarly, 29= a+20d (II)

subtracting equation I from II

29 = a + 20d

16 = a + 10d

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------------------------

13 = 10 d

d = 1.3

substituting d = 1.3 in equation I

16 = a+ 10 × 1.3

= a +13

a = 16 - 13

a = 3

now 41th term = 3+(41-1)1.3

= 3 + 52

= 55