Question

the 11th term and the 21th term of an ap are 16 and 29 respectively find the 41st term of this A.P.​

Answer 1

Answer:

41st term = 55

Step-by-step explanation:

t11 = 16  ,   t 21 = 29

a + 10d  = 16   equ (1)

a + 20d  = 29 equ (2)

on solving (1)  & (2)  we get  d = 13 /10   substitute   d= 13 /10 in equ (1)

we get a = 3

∴ 41 st term  = a + 40d

                    = 3 + 40 x 13/10

                   = 3 + 52

                 = 55