Question

the 11th term from the end of the Ap 10,7,4.......-62 is​

Answer 1

Step-by-step explanation:

The sequence given is 10, 7, 4, ....-62.

First we need to find out number of terms in this sequence.

'a' = 10, 'd' = -3, last term = -62

tn =a+(n−1)d

⟹ −62=10+(n−1)(−3)

⟹ −62=13−3n

⟹ 3n=75 or n=25.

The number of terms in the sequence is 25.

The 11th term from the end is same as the 15th term from the first.

So, 

t15=10+(15−1)(−3)

⟹t15=10+(14)(−3)

⟹t15=−32.

The 11th term from the end is -32.

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