Question

the 11th term of A.P. is 16 and 21st term of A. P. is 29. find 16th term of this A. P. ​

Answer 1

Answer:

2116=37 and term of 2916=315 37+315=352

Answer 2

Answer:

16th term of A. P. 22.5

Step-by-step explanation:

Let a be the first term and d the common difference of the A.P.

Here,$11^t$=16 and $21^t$=29.

tn=a+(n−1)d ….(Formula)

∴T11=a+(11−1)d

∴a+10=d …(1)

Similarly, t21=a+(21−1)d

∴a+20d=29 ....(2)

Adding equations (1) and (2), 2a+30d=45

∴a+15d=22.5 .. (Dividing both the sides by 2)

Now,t16=a+(16−1)d

∴t160=a+15d

=33.5 ...[From (3)]