Question

The 11th term of an A.p. exceeds its 4th term by 14. find the common difference

Answer 1

T11=T4+14
a+10d=a+3d+14
10d-3d=14
7d=14
d=2..

Answer 2

hi!!
here is your answer:

let, 11th term =a11

and 4th term =a4

according to question,


a11 =a4+14

a+10d=a+3d+14

7d=14

d=2

i hope u get ur answer!!