The 11th term of an A.p. exceeds its 4th term by 14. find the common difference
Answers
Answered by
9
T11=T4+14
a+10d=a+3d+14
10d-3d=14
7d=14
d=2..
a+10d=a+3d+14
10d-3d=14
7d=14
d=2..
Answered by
2
hi!!
here is your answer:
let, 11th term =a11
and 4th term =a4
according to question,
a11 =a4+14
a+10d=a+3d+14
7d=14
d=2
i hope u get ur answer!!
here is your answer:
let, 11th term =a11
and 4th term =a4
according to question,
a11 =a4+14
a+10d=a+3d+14
7d=14
d=2
i hope u get ur answer!!
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