Question

the 11th term of an ap -5, -52, 0, 52.....is
a.-20
b.20
c.-30
d.30
please answer step by step.....answer if u know only plssssssssss
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Answer 1

Answer:

$given \\ a = - 5 \\ d = - 52 - ( - 5) \\ = - 52 + 5 \\ = - 47 \\ \\ so \: \: \: \: a11 = a + (n - 1)d \\ = - 5 + (11 - 1) - 47 \\ = - 5 + 10 \times ( - 47) \\ = - 5 + ( - 470) \\ = - 5 - 470 \\ - 475$

Step-by-step explanation:

hope it helps u... and my answer is wrong becuase ur question is wrong as it is not forming an A. P.

Answer 2

Answer:

given

a=−5

d=−52−(−5)

=−52+5

=−47

soa11=a+(n−1)d

=−5+(11−1)−47

=−5+10×(−47)

=−5+(−470)

=−5−470

−475

Step-by-step explanation:

hope it helps u... and my answer is wrong becuase ur question is wrong as it is not forming an A. P.