Question

The 11th term of an AP is 16 and the 21st term is 29. Find the 16th term of the AP.​

Answer 1

Step-by-step explanation:

Given, t

11

=16 and t

21

=29.

We know that, t

n

=a+(n−1)d

∴t

11

=a+(11−1)d

and t

21

=a+(21−1)d

∴16=a+10d...(i)

and 29=a+20d...(ii)

Subtracting equation (i) from (ii), we get

10d=13⇒d=1.3

Putting the value of d in equation (i), we get

16=a+10(1.3)⇒a=3.

∴t

34

=3+(34−1)(1.3)

=3+33×1.3

t

34

=45.9

Answer 2

Answer:

22.5

Step-by-step explanation:

hope it will help you.....!