The 11th term of an AP is 80 and the 16th term is 110. What is the 31st term?
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Answer:
a11=80 , a16= 110 , a31=?
Step-by-step explanation:
A11= a+10 d =80 -----------1
A16= a+15d= 110------------2
subtract both the eq 1 from 2
-5d= -30
d=30/5 , d=6
now we can take out first term by putting values,
a11= a + 10d=80
a+ 10*6 = 80
a=80-60
a=20
now , A31= a+30d
= 20+ 30*6
=20+180
A31= 200
DONE YOUR QUESTION IS SOLVED
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