The 11th term of the GP : 1/8 , -1/4 , 2, -1 ..... is?
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Answer:
T₁₁ = 128
Step-by-step explanation:
a = 1/8
r = (-1/4)/(1/8) = -2
n=11
The nth term of a GP series is Tₙ = arⁿ⁻¹
T₁₁ = 1/8 . (-2)¹¹⁻¹
T₁₁ = 1/8 . (-2)¹⁰
T₁₁ = 1/8 . 1024
T₁₁ = 128.
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