Question

The 12 term of an ap exceeds the 5 term by 14 sum of both the term is 36 find 1 term an common difference

Answer 1

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12TH TERM EXCEEDS THE 5TH TERM BY 14

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IT MEANS 12TH TERM - 5TH TERM = 14

SO 7X = 14

SO 14/7

2

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SO THE COMMON DIFFERENCE IS 2.....

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12TH TERM = A + 11D

5TH TERM = A + 4D

A+11D+A+4D= 36

2A+15D= 36

BUT D = 2

SO

2A + 15*2=36

2A= 36-30

2A= 6

A= 6/2

A= 3

SO THE FIRST TERM IS 3

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